10-8x^2=-118

Solution for 10-8x^2=-118 equation:

10-8x^2=-118

We move all terms to the left:

10-8x^2-(-118)=0

We add all the numbers together, and all the variables

-8x^2+128=0

a = -8; b = 0; c = +128;
Δ = b2-4ac
Δ = 02-4·(-8)·128
Δ = 4096
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4096}=64$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-64}{2*-8}=\frac{-64}{-16}
=+4
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+64}{2*-8}=\frac{64}{-16}
=-4
$